Question

What is the solution of
`√(-1-2n) = n?`
Explain how you got your answer.

Answer 1

`√( - 1 - 2n) = n \\ = > ( √( - 1 - 2n )) ^(2) = {n}^(2) \\ = > - 1 - 2n = {n}^(2) \\ = > {n}^(2) + 2n + 1 = 0 \\ = > {(n)}^(2) + 2 * n * 1 + {(1) }^(2) = 0 \\ > {(n + 1)}^(2) = 0 \\ = > n + 1 = 0 \\ = > n = - 1`

Answer:

n = -1

Hope you could get an idea from here.

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