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2 votes
Principal root of this equation:
2cos(x) = √(2)

1 Answer

6 votes

Let's solve the equation:


\begin{gathered} 2\cos x=\sqrt[]{2} \\ \cos x=\frac{\sqrt[]{2}}{2} \\ x=\cos ^(-1)(\frac{\sqrt[]{2}}{2}) \\ x=(\pi)/(4) \end{gathered}

Therefore the principal root is:


(\pi)/(4)

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