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16 votes
16 votes
What is an equation of the line that passes through the point (-5,7)) and is parallel to the line x-5y=15

User Tibor Nagy
by
3.4k points

1 Answer

28 votes
28 votes

Answer: y=1/5x+8

Explanation:

Write the given equation in slope - intercept form:

-5y = -x+15

y = -(1/5)(-x+15)

y = (1/5)x -3.

The given slope is 1/5 and the required slope is -5.

Parallel lines have the same slope as the parent, the line goes through (-5,7) is y = mx+b with (x,y) = (-5,7) and m = 1/5.

7 = 1/5(-5) + b

-1+b=7

b=8

Therefore, the equation of the line is y=1/5x+8

User Chris McKenzie
by
2.8k points
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