Question

Help quick

subtract a³+b³-3 from the sum of 2a³-3b³+7 and -a³+b³+3ab-a​

Answer 1

Simplify the expression and solve.

• {(2a³- 3b³ + 7) + (-a³ + b³ + 3ab - a​)} - {a³ + b³ - 3}
• => {2a³- 3b³ + 7 - a³ + b³ + 3ab - a​} - a³ - b³ + 3
• => {a³- 2b³ + 7 + 3ab - a​} - a³ - b³ + 3
• => {a³- 2b³ + 7 + 3ab - a​} - a³ - b³ + 3
• => -3b³ + 7 + 3ab - a​ + 3
• => -3b³ + 10 + 3ab - a​

The solution to this algebraic problem is -3b³ + 10 + 3ab - a​.