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I really need help on this question because I have no idea how to go about solving this

I really need help on this question because I have no idea how to go about solving-example-1
User JBit
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Answer:

K'(-3, 6)

Explanation:

From the graph, the coordinates of G, H, and K are: G(1,3), H(6,0), and K(6,3).

If a point (x,y) is rotated 90 degrees counterclockwise about the origin, the transformation rule is:


(x,y)\to(-y,x)

Thus, the coordinates of the image points of the triangle GHK are:


\begin{gathered} G(1,3)\to G^(\prime)(-3,1) \\ H(6,0)\to H^(\prime)(0,6) \\ K(6,3)\to K^(\prime)(-3,6) \end{gathered}

The coordinates of the image of the point K is (-3,6).

User BrightIntelDusk
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