Question

Find the missing side lengths. Answers should be simplified radicals (no decimals).

Answer 1

Given:

The right triangle is given.

Use the sin ratio to find the hypotenuse of the triangle.

`\begin{gathered} \sin \theta=\frac{opposite\text{ side}}{\text{hypotenuse}} \\ \sin 45^(\circ)=\frac{2\sqrt[]{2}}{b} \\ \frac{1}{\sqrt[]{2}}=\frac{2\sqrt[]{2}}{b} \\ b=4 \end{gathered}`

Now, use the cosine ratio to find the remaining side of the triangle,

`\begin{gathered} \cos \theta=\frac{adjecent\text{ side}}{\text{hypotenuse}} \\ \cos 45^(\circ)=(a)/(4) \\ \frac{1}{\sqrt[]{2}}=(a)/(4) \\ a=2\sqrt[]{2} \end{gathered}`

Answer:

`\begin{gathered} a=2\sqrt[]{2} \\ b=4 \end{gathered}`