1 Answer

ChaosPredictor · Answer 1 · 2023-07-26T11:51:03+0000

Solution:

The possible outcomes:

The required probability is the probability of (doubles in 3 rolls) x (no doubles in 6 rolls)

$P(doubles\text{ in 3 rolls\rparen}=((6)/(36))^3*((5)/(6))^6=0.00155$

Therefore, the correct answer is 0.00155

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