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Write the equation of the line with slope -3/2 passes through the point (-12,16)​

User Clerenz
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1 Answer

12 votes
12 votes

Answer:

Explanation:

You have two pieces if information: the slope of a line and a point on the line. So you can use the "point-slope" formula in order to write the equation of this line. It is a fill-in-the-blank type of formula.

y - y1 = m(x - x1)

In this fill-in-the-blank formula the y1, the m, and the x1 will be filled in with the numbers you were given.

The problem gave the slope as -3/2 , this is your m. On these linear equation problems and formulas, m always stands for the slope.

So fill that in:

y - y1 = -3/2 (x - x1)

They also gave you a point, that is the (x1, y1) that you need to fill in the formula. The point was (-12, 16), so -12 will be your x1 and 16 will be your y1. Fill it in!

y - 16 = -3/2 (x - -12)

Simplify that ugly 'minus a negative' in the parenthesis.

y - 16 = -3/2 (x + 12)

If you were never told what form of equation to write, or they said "any form of the equation", then you're done!

This is in "point-slope" form.

y - 16 = -3/2(x+12) Ta-da!

If you need to change it to "slope-intercept' form then there are a few more steps.

y - 16 = (-3/2)x + (-3/2)12

y - 16 = (-3/2)x - 18

+16 +16

y = -3x/2 - 2 This is y=mx+b (called slope-intercept form)

User Grisha Levit
by
3.1k points
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