The larger number is 12 more than the smaller number
![x+12=y](https://img.qammunity.org/2023/formulas/mathematics/college/jkvjawkgiw5hju0kv6im0bd1yr5huae1pu.png)
the sum of the two numbers is 74; therefore,
![x+y=74](https://img.qammunity.org/2023/formulas/mathematics/college/wkbe1mszrqiv11gs1pvkjsohpvpd8w591l.png)
Therefore, we have two equations and two unknowns. We solve them by substitution
Putting in the first into the equation the second gives
![x+(x+12)=74](https://img.qammunity.org/2023/formulas/mathematics/college/7r8kl3tir2qtwy8lze94fh5zgvueed2nlu.png)
![2x+12=74](https://img.qammunity.org/2023/formulas/mathematics/college/tg0spzlr7i9m1ylb57udpdfmtufxkm7934.png)
subtracting 12 from both sides gives
![2x=62](https://img.qammunity.org/2023/formulas/mathematics/college/188o1p4pum6doefua65zoonmlh18v7ms1v.png)
Dividing both sides by 2 gives
![x=31.](https://img.qammunity.org/2023/formulas/mathematics/college/9fkt03js67hlsh4b73w9u7mlfxnnoi0q6e.png)
Hence, the the value of the smaller number is 31