ANSWER:
5.57 m/s
Explanation:
The magnitude of the velocity of each seat is given by the following equation:
![s=\sqrt[]{g\cdot x\cdot(\sin\theta)/(\cos\theta)}](https://img.qammunity.org/2023/formulas/physics/college/j1zcowi3vtk36awjvuds5glw34lpcf1mfo.png)
The value of x is the total extension of the seats from the center of the platform, we can calculate it as follows:

Replacing:
![\begin{gathered} s=\sqrt[]{9.8\cdot5.81\cdot(\sin \: 28.6)/(\cos \: 28.6)} \\ s=5.57\text{ m/s} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/1leq9bnceo5jutzc1gmt4e64c1wqzkvqe0.png)
The speed is 5.57 m/s