The claim states that "the population proportion of adults that has a cell phone is less than 94%"
The parameter of interest is the population proportion, symbolized as p
The claim is then

A sample of n=1194 and a sample proportion of p'hat=0.87 was obtained.
The test statistic you have to use to prove the claim is an approximation to the standard normal distribution:
![Z=\frac{p^(\prime)\text{hat-p}}{\sqrt[]{(p(1-p))/(n)}}\approx N(0,1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/3lmxaplje5lc7bh7vzndev13hm8nnmaq5l.png)
Replace the formula with the given values of the proportions and sample size to determine the value of the statistic under the null hypothesis:
![\begin{gathered} Z=\frac{0.87-0.94}{\sqrt[]{(0.94(1-0.94))/(1194)}} \\ Z=\frac{-0.07}{\sqrt[]{(0.0564)/(1194)}} \\ Z=-10.18 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/s5izzg0f0me785h48u7hu2ywqblwa7e8dd.png)
The value of the statistic is Z=-10.18