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I need help with the last one.True vale of density = 0.9973g/cm3 at 24°C

I need help with the last one.True vale of density = 0.9973g/cm3 at 24°C-example-1
User Kinzleb
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Percent error is used to calculate the difference between the true value versus the value found experimentally. It is calculated with the following equation:


\text{Percent error =}\frac{\text{ True value-Experimental value}}{\text{True value}}*100

Experimental value =0.994g/cm3

True value = 0.9973 g/cm3

Now, we will replace the known values in the equation:


\begin{gathered} \text{Percent error =}\frac{\text{ 0.9973g/cm}^3\text{-0}.994\text{g/cm}^3}{\text{0.9973g/cm}^3}*100 \\ \text{Percent error =}0.33 \end{gathered}

So, the percent error will be 0.33%

User Zalogatomek
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