Answer:
x + 2tan X . sec X / X
Explanation:
The derivatives of trigonometric functions is as follows
* d/dx (sin x) = cos x
* d/dx (cos x) = - sin X
* d/dx (tan x) = sec ^2 X
* d/dx (Cot x) = -cosec^2 X
* d/dx (sec x) = tan x . sec x
* d/dx (cosec x) = -cot x . cosec x
and so the derivative of sec is tanx . sec x
d/dx x - sec x
the derivative of variables is considered 1.
since we remove 1 from their exponent they'll have 0 as their exponent which can only mean the end value is 1.
so d/dx of X is = 1
d/dx od -sec X is = -tan X . Sec X based on the general derivative properties above.
in conclusion the final answer is = x + 2tan X . sec X / X