Given that the length of the wire is l = 0.2 m
The radius of the wire is r = 1 cm = 0.01 m
The resistance of the wire is
![R\text{ = 3.2}*10^(-5)\Omega](https://img.qammunity.org/2023/formulas/physics/college/w2sh95xt1yqbwcszn1wquzxqvpn15qsyoc.png)
We have to find the resistivity of the metal.
Resistivity can be calculated by the formula,
![\begin{gathered} \rho=\text{ }\frac{Resis\tan ce\text{ }* Area}{length} \\ =(R\pi r^2)/(l) \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/ev8hr1bmmgkv1dpb7cr3gehxwhrf5a9oug.png)
Substituting the values, the resistivity will be
![\begin{gathered} \rho\text{ =}(3.2*10^(-5)*\pi*(0.01)^2)/(0.2) \\ =5.0\text{ }*10^(-8)\Omega\text{ m} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/ghmvv56nolblia2fc7dlrghg6gjrzdk6ar.png)
Thus, the resistivity of the metal is 5.0 x 10^(-8) ohm-meter.