1 Answer

Reznic · Answer 1 · 2023-09-16T15:58:57+0000

The surface area of this triangular prism is given by the sum of the area of its five sides.

The are a of each one of the two triangular sides is given by:

$(1)/(2)\cdot3\cdot4=6\text{ cm}^2$

The area of the rectangular base is given by:

$4\cdot11=44\text{ cm}^2$

The area of the rectangular side perpendicular to the base is given by:

$3\cdot11=33\text{ cm}^2$

The area of the upper side is given by:

$5\cdot11=55\text{ cm}^2$

Therefore, the total area is:

$2\cdot6+44+33+55=144\text{ cm}^2$

Answer: 144 cm²

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