Question

The width of a rectangle is 2 its length. The perimeter of the rectangle is 540 ft. What is the length, in feet, of the rectangle?

Answer 1

To solve this problem we can write one equation for each condition so:

the width of a rectangle is 2 its length so:

`W=2L`

and one for the perimeter so:

`2W+2L=540`

Now we replace the first equation into the second one so:

`\begin{gathered} 2(2L)+2L=540 \\ 4L+2L=540 \\ 6L=540 \\ L=(540)/(6) \\ L=90 \end{gathered}`

So the length of the rectangle is 90 ft