Question

What does sin(pi + theta) + cos(pi/2 - theta) simplify to? sin theta + cos theta 2 cos theta 0 1

Answer 1

0

Step-by-step explanation:

We utilise the following two properties of sines and cosines to simplify our expression.

`\sin(\pi+x)=-\sin(x)`

and

`\cos((\pi)/(2)-x)=\sin(x)`

Substituting the above simplifications into our expression gives

`\sin(\pi+x)+\cos((\pi)/(2)-x)\rightarrow-\sin(x)+\sin(x)=0`

Therefore we conclude that

`\boxed{\sin(\pi+x)+\cos((\pi)/(2)-x)=0.}`