Question

Point A is located at (4x -8, y-11).Point B is located at (4x +8, y-17).What is slope of the line?

Answer 1

Given:

Point A is located at (4x -8, y-11). Point B is located at (4x +8, y-17).

To find:

The slope of the line.

Solution:

It is known that the slope of the line passing through the points (x1, y1) and (x2, y2) is given by:

`m=(y_2-y_1)/(x_2-x_1)`

So, the required slope is:

`\begin{gathered} m=((y-17)-(y-11))/((4x+8)-(4x-8)) \\ =(y-17-y+11)/(4x+8-4x+8) \\ =(-6)/(16) \\ =(-3)/(8) \end{gathered}`

Thus, the slope of the line is -3/8.