We have the next given information:
-Ashley's fish tank has 15 liters of water in it.
- She plans to add 4 liters per minute until the tank has at least 59 liters
We can write at least using the inequality symbol for greater than or equal to "≥".
Now, we can write the next inequality:
![\begin{gathered} 4t+15≥59 \\ \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/buiz8kzvmyjdszvvpf8fhpb74uag9vs2es.png)
Where the t is the dependent variable, and it depends on the liter per minute.
we add 15 because the tank has already 15 liters of water in it.
Solve for t:
![\begin{gathered} 4t≥59-15 \\ 4t≥44 \\ t≥(44)/(4) \\ t≥11 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/y6kbmxrty1lh6mmzz3y5ftl2ijbb1iyw3k.png)
So Ashley could add water for at least 11 minutes.
The inequality answer is t≥11.