Question

An initially stationary object experiences an acceleration of 6 m/s^2 for a time of 15s. How far will it travel during that time?x = xo + vo t + ½ a t^2 g = 9.8 m/s2 (downward)

Answer 1

`675m`

Step-by-step explanation

Parameters given:

Initial velocity, v0 = 0 m/s

Acceleration, a = 6 m/s^2

Time, t = 15s

To find the distance traveled during that time, we have to apply one of Newton's equations of motion:

`x=ut+(1)/(2)at^2`

Therefore, we have:

`\begin{gathered} x=(0\cdot15)+((1)/(2)\cdot6\cdot15^2) \\ x=0+675 \\ x=675m \end{gathered}`

That is the distance traveled during that time.