Question

Find the equation of the line that contains the point (-3,1) and is perpendicular tothe line x = 4. Write the line in slope-intercept form, if possible. Graph the lines.

Answer 1

Note that a horizontal line has a slope of 0.

From the problem, we have a line x = 4 which is a vertical line and any line that is perpendicular to a vertical line is a horizontal line.

We need to find the equation of the line perpendicular to x = 4 and contains the point

(-3, 1).

Since the line will be a horizontal line, the slope will be 0.

Using point-slope formula :

`y-y_1=m(x-x_1)`

where (x1, y1) is a point on the line and m is the slope.

This will be :

`\begin{gathered} y-1=0(x+3) \\ y-1=0 \\ y=1 \end{gathered}`

The answer is y = 1

The graph will be :