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What is the equation of the line that passes through the point (-5,1)(−5,1) and has a slope of -\frac{1}{5}−5​

User Rbatt
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1 Answer

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20 votes

Answer:

Explanation:

I will interpret "-\frac{1}{5}−5​" as -(1/5).

We'll look for an equation by starting with the slope intercept format of:

y = mx + b,

where m is the slope and b is the y-intercept (the value of y when x=0).

We are given the slope of -(1/5), I think.

The equation becomes y = -(1/5)x + b

We want to find a value of b that will force the line to go through point (-5,1). Do this by putting this point into the equation we have thus far:

y = -(1/5)x + b

1 = -(1/5)*(-5) + b [point (-5,1)]

1 = 1 + b

b = 0

The equation becomes y = -(1/5)x + 0, or y = -(1/5)x

See the attachment.

What is the equation of the line that passes through the point (-5,1)(−5,1) and has-example-1
User EdNdee
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3.2k points