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Write an equation of a line that is perpendicular to y=5/6x-3 and has a y-intercept of -11
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Write an equation of a line that is perpendicular to y=5/6x-3 and has a y-intercept of -11

User Ariful
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1 Answer

3 votes

Answer:


y=-(6)/(5)x-11

Explanation:

Perpendicular lines have slopes that are negative reciprocals of each other. The slope of the given line is 5/6, so the slope of the line we want to find is -6/5.

So, the equation is
y=-(6)/(5)x-11.

User Mugabo
by
3.4k points
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