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If the horizontal force of 200N is sufficient to start moving a body of mass 50Kg along awooden floor. Calculate the coefficient of friction (take gravity = 10ms-2). What typeof coefficient of friction is it?

User Animesh
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1 Answer

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Given:

• Horizontal force, Fx = 200 N

,

• Mass of body = 50 kg

,

• Acceleration due to gravity, g = 10 m/s².

Let's find the coefficient of friction.

To find the coefficient of friction, apply the formula:


F=F_n*\mu

Where:

f is the frictional force = 200 N

Fn is the normal force.

μ is the coefficient of friction.

To find Fn, we have:

Fn = m x g = 50 x 10 = 500 N

Thus, to find the coefficient of friction, we have:


\begin{gathered} \mu=(f)/(F_n) \\ \\ \mu=(f)/(m*g) \\ \\ \mu=(200)/(500) \\ \\ \mu=0.4 \end{gathered}

Therefore, the coefficient of friction is 0.4

The type of coefficient of friction is the static friction coefficient.

ANSWER:

• Coefficient of friction = 0.4

• Static friction coefficient.

User Arvik
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