Question

Find y if the distance between points p (3, -18) and r (10,y) is located in the first quadrant

Answer 1

For this case we can use the following formula:

`d=\sqrt[]{(y+18)^2+(10-3)^2}`

And d = 25 so we can replace and we got:

`25^2=(y+18)^2+49`
`576=(y+18)^2`

taking square root we got:

`24=y+18`

y= 24-18 = 6

then the value of y is equal to 6