Question

I need help question. Part BAnswer from part A is 199.5

Answer 1

We are asked to determine the average of the function:

`f(x)=9x+8`

In the interval:

`[5,8]`

To do that we will use the following formula:

`avg=(1)/(b-a)\int_a^bf(x)dx`

Where "a" and "b" are the extreme points of the interval.

Now, we substitute the values:

`avg=(1)/(8-5)\int_5^8(9x+8)dx`

From part A we know that the value of the integral is 199.5. Now, we plug in the value of the integral:

`avg=(1)/(8-5)(199.5)`

Solving the operations:

`avg=66.5`

Therefore, the average of the function in the given interval is 66.5