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Pls help!!! need answer asap!!

Pls help!!! need answer asap!!-example-1
User Isyi
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1 Answer

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Answer:

The distance travelled by bus is 281.25 km and the distance travelled by airplane is 1,618.75 km.

Explanation:

Let's use b for bus and a for airplane

We know that distance = speed × time

The total distance is 1900 km

x + y = 1900

Average speed by bus = 60km/h or x/60 h

Average speed by plane = 700km/h or y/700 h

Total travelling time = 7h

So we write the equation as:

x/60 + y/700 = 7

First we need to solve for y in the equation x + y = 1900

x + y = 1900

Subtract x from both sides

x - x + y = 1900 - x

y = 1900 - x

Now that we have y, we can substitute y in the equation x/60 + y/700 = 7

x/60 + y/700 = 7

x/60 + 1900 - x / 700 = 7

And now we solve for x in the equation: x/60 + 1900 - x / 700 = 7

x/60 + 1900 - x / 700 = 7

Multiply both sides of the equation by 2100, the least common multiple of 60,700

35x + 3(1900 − x) = 14700

Use the distributive property to multiply 3 by 1900 − x

35x + 5700 − 3x = 14700

Combine 35x and −3x to get 32x

32x + 5700 = 14700

Subtract 5700 from both sides.

32x + 5700 - 5700 = 14700 − 5700

Subtract 5700 from 14700 to get 9000

32x = 9000

Divide both sides by 32.

32x/32 = 9000/32

Reduce the fraction 9000/32 to lowest terms by extracting and cancelling out 8.

x = 9000/32

x = 281.25

Now that we have x, we can solve for y in the equation: y = 1900 - x

y = 1900 - x

Substitute x with 281.25

y = 1900 - 281.25

Subtract 281.25 from 1900 to get

y = 1618.75

So, the distance travelled by bus is 281.25 km and the distance travelled by airplane is 1618.75 km.

User NayabSD
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