Question

Help with number three parts a-d are all number three

Answer 1

For this problem, we are told that a bag contains a number from 1 to 10, we need to calculate the probability of a few situations.

The probability of any given event occurring is the division between the favorable events and all the possible events.

The first one is the probability of drawing a number between 2 and 7. There are 6 possible numbers we can draw, 2, 3, 4, 5, 6 and 7, from a total of 10 possible numbers, therefore we have:

`P(\text{ between 2 and 7})=(6)/(10)=(3)/(5)`

The probability is 3/5.

Now we need to determine the probability of the number is a multiple of 5. There are only two multiples of 5 among the possible results, which are 5 and 10. Therefore we have:

`P(\text{ multiple of 5})=(2)/(10)=(1)/(5)`

The probability is 1/5.

Now we need to describe the compliment of selecting a 9. The complement of a certain event is the same as the probability of that event not happening. Therefore the complement of selecting a 9 represents not selecting a 9, selecting any other possible number instead.

If the probability of selecting the number is 3/10. The question could be "The probability of selecting a multiple of 3", because there are only 3, 6 and 9 as favorable events.