Question

54 y Use the graph of f(x) to explain the relationship between the real zeros of flx) and its intercept(s). 4 3 27 1 (4,0) 5 4 - 2 Of(x) has one real zero at -2 because the graph of the function has an intercept at (0.-2). Of(x) has two real zeros at-4 and -2 because the graph of the function has intercepts at (-4, 0) and (0, -2). f(x) has no real zeros because the graph of the function does not pass through (0,0). O f(x) has one real zero at -4 because the graph of the function has an intercept at (-4,0). 1 2 3 4 (0-2) 10

Answer 1

The first assertive says that f(x) has a real zero at -2. What is wrong! We can see in the graph it has a zero at (-4,0). x=-4.

The second assertive says that f(x) has two zeros: at -4 and -2. That is wrong, because we say that is a zero when it crosses the X-axis, not the Y.

The third assertive says it has no zeros, because the graph does not pass through (0,0). But to have a zero does not mean it goes through the origin of the system.

The fourth assertive is right, because it says it has an intercepf at (-4,0), and for this reason, it has one zero.