Answer:
4C4HO + 4Cl2 + 13O2 → 14CO2 + 2CCl4 + 2H2O
Step-by-step explanation:
Balance The Equation: C4HO + Cl2 + O2 = CO2 + CCl4 + H2O
1. Label Each Compound With a Variable
aC4HO + bCl2 + cO2 = dCO2 + fCCl4 + gH2O
2. Create a System of Equations, One Per Element
C: 4a + 0b + 0c = 1d + 1f + 0g
H: 1a + 0b + 0c = 0d + 0f + 2g
O: 1a + 0b + 2c = 2d + 0f + 1g
Cl: 0a + 2b + 0c = 0d + 4f + 0g
3. Solve For All Variables
a = 4
b = 4
c = 13
d = 14
f = 2
g = 2
4. Substitute and Verify Result
4C4HO + 4Cl2 + 13O2 = 14CO2 + 2CCl4 + 2H2O
L R
C: 16 16 ✔️
H: 4 4 ✔️
O: 30 30 ✔️
Cl: 8 8 ✔️
hope this helps! :D