Question

Evaluate.

16÷(2+1/2)2

(the 2 at the end is a 1 half to the 2 power)

Answer 1

PEMDAS, notice Parentheses is first, then Exponents 2nd

`16/\left(2 + \left( (1)/(2) \right)^2 \right)\implies 16/\left(2 + \left( (1^2)/(2^2) \right) \right)\implies 16/\left(2+(1)/(4) \right)`

now that the exponent got done, let's keep in the parentheses

`16/\left((2)/(1)+(1)/(4) \right)\implies 16/\left(\cfrac{8+1}{\underset{\textit{using this LCD}}{4}} \right)\implies 16/ \left( \cfrac{9}{4} \right)`

PEMDAS, after all that we'll do D, Division next

`16/ \left( \cfrac{9}{4} \right)\implies \cfrac{16}{1}/ \cfrac{9}{4}\implies \cfrac{16}{1}\cdot \cfrac{4}{9}\implies \cfrac{64}{9}\implies 7(1)/(9)`

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this just some addition to your previous posting, since you kinda got spammed some

`\stackrel{\stackrel{\textit{E first}}{\downarrow }}{2^3}+4\cdot 2-7\implies 8+4\cdot 2-7\implies 8+\stackrel{\stackrel{\textit{M second}}{\downarrow }}{8}-7\implies \stackrel{\textit{AS last from left to right}}{16-7\implies 9}`

notice, PEMDAS, P first and so on, AS are last, from left to right.