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The difference of two numbers is 16. But large number is five less than four times the smaller number. Find the two numbers.

User Baron
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1 Answer

5 votes

Let x be the larger number and y be the smaller number.

Given the difference between two numbers is 16.


x-y=16\ldots\text{..}(1)

Given larger number is five less than four times the smaller number.


x=4y-5\ldots\text{.}\mathrm{}(2)

Now, solve the equation (1)


x=16+y

Put x in the 2nd equation.


\begin{gathered} 16+y=4y-5 \\ 4y-y=16+5 \\ 3y=21 \end{gathered}

Further solved as,


y=7

Now, put the value of y in equation (1)


\begin{gathered} x-y=16 \\ x-7=16 \\ x=16+7 \\ x=23 \end{gathered}

Thus,


x=23

Therefore, the two numbers are 23 and 7.

User Peroija
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