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8 votes
8 votes
Can anyone answer this question please
6[y-2]/7-12=2[y-7]/3

User Bogdan Gusiev
by
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1 Answer

21 votes
21 votes

Answer:

y =47.5.

Explanation:

First eliminate the fractions by multiplying through by the LCM of 7 and 3 which is 21:

21* 6[y-2]/7-21*12 = 21*2[y-7]/3

18(y - 2) - 252 = 14(y - 7)

18y -36 - 252 = 14y - 98

18y - 14y = -98 + 36 + 252

4y = 190

y = 190/4

y = 47.5.

User Tomgalpin
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