Question

Need help please and thank you.​

Answer 1

`log_4((1)/(64))=-3`

Explanation:

`log_b(b^x)=x`

• Let b = base and x = the exponent

Looking at the equation given, we know the base (the number with the exponent) is 4, the exponent itself is -3, and the value is 1/64. Based on this information, fill in the formula and simplify any values.

`log_4(4^(-3))=-3\\log_4((1)/(64))=-3`

Therefore, the logarithmic form is
`log_4((1)/(64))=-3`.