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Write an equation for the line that passes through the given point and is parallel to the graph of the given equation1. 3x + 4y = 12 ; (-4, 7)

User Anju
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1 Answer

6 votes

We can rewrite the equation of the given line from 3x + 4y = 12 to the slope-intercept form like this:

3x + 4y = 12

3x - 3x + 4y = 12 - 3x

4y = 12 - 3x

y = (12 - 3x)/4

y = 12/4 - 3/4x

y = 3 - (3/4)x

As you can see, the slope of this line is -3/4, since this line is parallel to the line that passes through the point (-4, 7), their slopes are the same, then we can write the equation of the second line in slope-intercept form to get:

y = -3/4x + b

By replacing the x and y-coordinates of the point (-4, 7) where the line passes through, we get:

7 = (-3/4)(-4) + b

7 = 3 + b

7 - 3 = b

4 = b

b = 4

By replacing 4 for b, into the above equation, we get: the equation of the line parallel to 3x + 4y = 12 and that passes through (-4, 7):

y = -3/4x + 4

User Jason Spradlin
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