Answer:
Explanation:
x² + 8x + 12 = 0
➺ x² + 2x + 6x = 0
➺ x(x + 2) + 6(x + 2) =0
➺ (x + 6)(x + 2) = 0
Whether, x + 6 = 0
⠀⠀⠀⠀⠀➺ x = -6
⠀⠀or,⠀⠀⠀⠀ x + 2 = 0
⠀⠀⠀⠀⠀⠀➺ x = -2
Hi,
a= 1 ; b= 8 c= 12
∆ = b² - 4ac
∆ = 8² - 4*1*12
∆ = 64 - 4*12
∆ = 64 - 48
∆ = 16
∆>0 :
x1 = (-b-√∆)/2a = (-8-4)/2 = -12/2 = -6
x2 = (-b+√∆)/2a = (-8+4)/2 = -4/2 = -2
S= { -6 ; -2 }
x = -6
or x = -2
✅(•‿•)
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