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In a circle , a 60 ° sector has area 25pi . What is the circumferenceof the circle ? Leave your answer in terms of and in simplest radical form .

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ANSWER:


c=10\sqrt[]{6}\pi

Explanation:

To calculate the area of the entire circle we must do it by means of a proportion, since the entire circle is 360 °, therefore


(25\pi)/(60)=(x)/(360)

Solving for x:


\begin{gathered} x=(360\cdot25\pi)/(60) \\ x=150\pi \end{gathered}

After calculating the area we can calculate the value of the radius, knowing that:


\begin{gathered} A=\pi\cdot r^2 \\ \text{solving for r} \\ 150\pi=\pi\cdot r^2 \\ r=\sqrt[]{150} \\ r=5\sqrt[]{6} \end{gathered}

Now, the formula for the circumference is the following:


\begin{gathered} c=2\pi r \\ c=2\pi\cdot5\sqrt[]{6} \\ c=10\sqrt[]{6}\pi \end{gathered}

User Damali
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