we have
The sum of two numbers is 92. One eighth of the first number plus one third of the second number is 19. Find the numbers.
Let
x ------> first number
y -----> second number
the algebraic expression that represent this situation is
x+y=92 ------> equation A
(1/8)x+(1/3)y=19
Multiply both sides by 24
3x+8y=456 ------> equation B
solve the system of equations
Isolate teh variable x in the equation A
x=92-y ------> equation C
substitute equation C in equation B
3(92-y)+8y=456
solve for y
276-3y+8y=456
5y=456-276
5y=180
y=36
Find the value of x
x=92-36
x=56
therefore
the numbers are 56 and 36