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In order for the parallelogram tobe a square, x = [?].4x + 1712x - 23

In order for the parallelogram tobe a square, x = [?].4x + 1712x - 23-example-1
User PromInc
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1 Answer

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By definition, the diagonals of a square bisect each other, so these diagonals are perpendicular, which means that they form a Right angle (90 degrees) when they intersect. The diagonals of a square have equal length.

In this case, you in order for the parallelogram to be a square:


4x+17=12x-23

Then, you can solve for the variable "x":


\begin{gathered} -12x+4x=-23-17 \\ -8x=-40 \\ \\ x=(-40)/(-8) \\ \\ x=5 \end{gathered}

Therefore, the answer is:


x=5

User Taras Kozubski
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