171k views
1 vote
The table below shows the scores of a group of students on a 10-point quiz.Test ScoreFrequency3 54 15 16 27 28 49 310 1The mean score on this test is: _________________The median score on this test is: ____________________

User Holzben
by
4.9k points

1 Answer

5 votes

Step-by-step explanation

Part A

We can use the formula below to find the mean.


\text{Mean}=\sum ^{}_{}((fx)/(f))

We will then have;


\begin{gathered} \text{Mean = }(5*3+4*1+5*1+6*2+7*2+8*4+9*3+10*1)/(19)=(15+4+5+12+14+32+27+10)/(19) \\ =(119)/(19)=6.2632 \end{gathered}

Mean = 6.2632

Part B

Since the data set is odd.


\begin{gathered} \text{Median}=((n+1))/(2)^(th)\text{observation} \\ =\text{Value of }\frac{\text{(19+1)}}{2}^(th)\text{observation} \\ =\text{value of 10th observation} \end{gathered}

Answer: From the column of cumulative frequency cf, the median is 7

User AdamG
by
5.4k points