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Question is in image
In the diagram below, ST is parallel to PR

Question is in image In the diagram below, ST is parallel to PR-example-1
User VarunRajendran
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1 Answer

17 votes
17 votes

Answer:

D.

Explanation:

There is nothing in the figure to indicate the triangles are isosceles. This eliminates answer choices A, B, C.

Answer choice D is a required step in the proof, but only gets part of the way. The triangle similarity means ...

SQ/PQ = TQ/RQ

From here, you need to decompose each of the sides PQ and RQ into parts. Then you can get to the desired relationship.

(PQ -PS)/PQ = (RQ -RT)/RQ . . . segment sum theorem

1 - PS/PQ = 1 -RT/RQ . . . . . . . do the division

-PS/PQ = -RT/RQ . . . . . . . . subtract 1 (subtraction property of equality)

PS/PQ = RT/RQ . . . . . . . . multiply by -1 (multiplication property of equality)

User Achingfingers
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