Question

Given the number of trials and the probability of success, determine the probability indicated: (Hint use binomial distribution formula use factorials ! in showing your work no calculator only by hsndstep-by-step use calculator determine final answer only use Calculator to simplify please show step-by-step)n = 15, p = 0.4, find P(4 successes) n = 12, p = 0.2, find P(2 success ) n = 20, p = 0.05, find P(at most 3 successes) (hint for c. P (at most 3 successes) = P(x ≤3)= P(x= 0) + P(x = 1)+ P(x = 2)+ P(x = 3)

Answer 1

a.

`\begin{gathered} n=15 \\ p=0.4 \\ \\ P(X=4)=C(15,4)*(0.4)^4*(0.6)^(11) \\ \\ P(X=4)=(15!)/(11!4!)*(0.4)^4*(0.6)^(11) \\ \\ P(X=4)=(15*14*13*12*11!)/(11!*24)*(0.4)^4*(0.6)^(11) \\ \\ P(X=4)=1365*(0.4)^4*(0.6)^(11) \\ \\ P(X=4)=0.127 \end{gathered}`

b.

`\begin{gathered} n=12 \\ p=0.2 \\ \\ P(X=2)=C(12,2)*0.2^2*0.8^(10) \\ \\ P(X=2)=(12!)/(10!2!)*0.2^2*0.8^(10) \\ \\ P(X=2)=(12*11*10!)/(10!*2)*0.2^2*0.8^(10) \\ \\ P(X=2)=66*0.2^2*0.8^(10) \\ \\ P(X=2)=0.283 \end{gathered}`

C.

`\begin{gathered} n=20 \\ p=0.05 \\ \\ P\left(x≤3\right)=P\left(x=0\right)+P\left(x=1\right)+P\left(x=2\right)+P\left(x=3\right) \\ \\ P\left(x≤3\right)=0.984 \end{gathered}`