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11 votes
11 votes
Hello help me with this question thanks in advance​

Hello help me with this question thanks in advance​-example-1
User Rickardo
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2 Answers

9 votes
9 votes

Answer:

1) 100/2 = 50°.

2) 50°

3) 50°

Reasons: rhombus, perpendicular bisector

- Toodles!~

User Shontelle
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22 votes
22 votes


\bold{\huge{\pink{\underline{ Solutions}}}}

Answer 18 :-

We have,

Rhombus RAMS and Angle SMA = 100°

  • In rhombus, The diagonals bisect each other at an angle of 90° .

Therefore,


\sf{\angle{ AMR = 1/2}}{\sf{\angle{ SMS}}}


\sf{\angle{ AMR = 1/2 × 100 }}


\sf{\angle{ AMR = 50° }}

Thus, Angle AMR is 50°

Hence, Option D is correct

Answer 19 :-

We know that,

  • The sides of rhombus are equal and parallel to each other


\sf{\angle{ AMR = }}{\sf{\angle{ RMS}}}

[ Alternative interior angles ]


\sf{\angle{ RMS = 50° }}

Thus, The value of Angle RMS is 50°

Hence, Option B is correct

Answer 20 :-

Here, we have to find the value of mAngleMSA

In ΔCMS,

By using Angle sum property


\sf{ 50° +}{\sf{\angle{MSC + 90° = 180° }}}


\sf{\angle {MSC = 180° - 140°}}


\sf{\angle{MSC = 40° }}

Therefore,


\sf{m}{\sf{\angle{MSA = 40° }}}

Thus, The value of mAngle MSA is 40°

User Giorgos
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