Question

Find the X and the Y intercepts of the graph of the equation below 8x + 2y equals negative 16

Answer 1

The expresion is:

`8x+2y=-16`

to find the intercepts with the x axis we have to rplace in the equation y = 0, so:

`\begin{gathered} 8x+2(0)=-16 \\ 8x=-16 \end{gathered}`

and we solve for x

`x=-(16)/(8)=-2`

the intersection with the x axis is -2

And for the itercepts with the y axis we replace x = 0

`\begin{gathered} 8(0)+2y=-16 \\ 2y=-16 \end{gathered}`

and we solve for y

`y=-(16)/(2)=-8`

This means that the intersepts with the y axis is -8