Answer: 26g
Step-by-step explanation:
First, write the correctly balanced equation for the reaction taking place:
HBr(aq) + NaOH(s) ==> NaBr(aq) + H2O(l) ... balanced equation
Next, find out which reactant is limiting. An easy way is to just divide the moles of each reactant by the corresponding coefficient in the balanced equation (1 for both in this case):
HBr: 46.1 g HBr x 1 mol HBr / 80.9 g = 0.570 moles
NaOH: 10. g NaOH x 1 mol NaOH / 40. g = 0.25 mols NaOH
NaOH is limiting and will determine the maximum amount of product that can form.
Maximum amount of NaBr that can form:
0.25 mols NaOH x 1 mol NaBr / 1 mol NaOH x 103 g NaBr / mol = 25.75 g NaBr = 26 g NaBr (2 s.f.)