Question

When three squares are joined at their vertices to form a right triangle, the combined area ofthe two smaller squares is the same as the area of the largest square.Which three squares do NOT support this statement?21 cm25 cm3 cmH9 cm4 cm144 cm13 cm100 cmG5 cm36 cm64 cm12 cm

Answer 1

H.

1) In this problem, we have to check out which one of those trios the Pythagorean Theorem doesn't work for the given measures.

F ) a² =b² +c²

5² = 3²+4² True Classic Pythagorean Triple 3,4 ,5

G) 5, 12, 13

13² = 5² +12² Another classic Pythagorean Trio for right triangle 5,12,13

169 = 25 +144 True

H) We have the following measures: hypotenuse of that triangle to be 21, 9, and 12, since the area of the square is l²=144 then l =12, writing the measurements plugging into the Pythagorean Theorem and taking 21 as the larger side (possible hypotenuse):

a²=b² +c²

21² ≠ 9² +12 ²

441 ≠ 81 +144

441 ≠ 225 FALSE

So the junction of those three sides does not yield a right triangle.

I) 10² = 8² +6² True