Question

Find the slope of the secant line for k(x) = -12 SQRT x between x = 2 and x= 6

Answer 1

Given:

`k(x)=-12\sqrt[]{x}\text{ betw}een\text{ x=2 and x=6}`

The slope is calculated as,

`\begin{gathered} m=(f(b)-f(a))/(b-a) \\ m=(f(6)-f(2))/(6-2) \\ m=\frac{-12\sqrt[]{6}-(-12\sqrt[]{2})}{4} \\ m=\frac{-12\sqrt[]{6}+12\sqrt[]{2}}{4} \\ m=(12)/(4)(\sqrt[]{2}-\sqrt[]{6}) \\ m=3(\sqrt[]{2}-\sqrt[]{6}) \\ m=-3.11 \end{gathered}`

Answer: slope of the secant line is -3.11.