Given: The thickness of a dime and a dollar as shown below
![\begin{gathered} T_{\text{hickness of dime}}=0.135cm \\ T_{\text{hickness of a dollar}}=1.0922*10^(-2)cm \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/rn4yt08rec0x0vbfrvptyin1ag94u9oqcw.png)
To Determine: How many times thicker is the dime than the dollar bill
Solution:
Step 1: Convert the thickness of the dollar bill from standard form to ordinary form
![1.0922*10^(-2)=0.010922cm](https://img.qammunity.org/2023/formulas/mathematics/college/5k2tsleper09xeeivkfkgzxpo40zt4sjd0.png)
Step 2: Divide the thickness of the dime by the thickness of the dollar bill
![\begin{gathered} (0.135cm)/(0.010922cm) \\ =12.36 \\ \approx12 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1apyedny9imxcgkge6cqvq952eimp7afiu.png)
Hence, the dime is about 12 times thicker than the dollar bill