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Solve the linear / quadratic system and give the values of x that satisfy it5x²+2x+5=yy-6=2x

User IMJS
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1 Answer

4 votes

From the second equation we solve for y to get:


y=2x+6

Plugging the above value of y into the first equation gives


5x^2+2x+5=2x+6

Subtracting 2x from both sides gives


5x^2+5=6

and subtracting 5 from both sides gets us


5x^2=1

Finally, divide both sides by 5 and then take the square root to get


\textcolor{#FF7968}{x=\pm\frac{1}{\sqrt[]{5}}}

which is our answer!

User Huanian Zhang
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4.3k points