Question

Part II Dilution Problems: 16. A 1.2 molar solution of HCl is diluted to a final concentration of 0.53 mol/L. If the final volume is 950 mL, what was the original volume of the solution? How much water was added? 17. 350.0 mL of water was added to a 2.3 L solution of Naci. If the final concentration of the solution was 0.967 M, what was the original concentration of the solution? 18. 3.57 L of a 1,3 M solution of NaBr is diluted to a final concentration of 1.23 M. What is the final volume of the solution? 19. 350.0 mL of water was added to 700.0 mL of a 2.0 M solution of NaCl. What was the final concentration of the solution? 20. A bottle is labeled 12,0 M HCI. What volume of the original HCl is required to make 20.0 mL of 3.0 M HCl solution?

Answer 1

The volume of water added is 530 mL

The initial volume is 420 mL

Step-by-step explanation:

Here, we want to get the original volume of the solution and the volume of water added

Mathematically, according to the dilution formula, we have that as:

`C_1V_1\text{ = C}_2V_2`

Where:

C1 and V1 are the molarity and volume of the first solution

C2 and V2 are the molarity and volume of the second solution

Substituting the values, we have it that:

`\begin{gathered} 1.2\text{ }*\text{ V}_1\text{ = 0.53 }*\text{ 950} \\ V_1\text{ = }(0.53*950)/(1.2) \\ \\ V_1\text{ = 420 mL} \end{gathered}`

The above is the initial volume

To get the amount of water added, we subtract the above from the final volume

Mathematically, we have that as:

`950\text{ mL - 420 mL = 530 mL}`